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A boy goes to the school with the speed of 3 km/hr and returns with the speed of 2 km/hr. If he takes 5 hours, in all, then how do you find the distance (in km) between house to the school? Answer :- Let the distance be x km S 1 = 3km/h         S 2 = 2km/h d = x km             d = x km t 1 = d/s = d/3     t 2 = d/s = d/2 Total  Time = t 1 +t 2 = 5   ð    => d/2 +  d/3 = 5   ð    3x + 2x / 6 = 5   ð    5x = 30   ð    x = 30/5       = 6 km the distance between house to the school is 6 km

1. Find the formula and C. I on Rs 2500 for 2 years at 10% per annum.  2. Find the amount and C. I on Rs 40,000 for 3 years at 5 % per annum. Answer :- (i) Given Principle (P) = rs. 2500 Time (t) = 2 years Rate of interest (R) = 10% We know that Putting all above values in this equation So Amount = Rs. 3025 Now, CI = Amount - Principle CI =Rs. (3025 – 2500) CI = Rs. 525 (ii) Given Principle (P) = Rs. 40000 Time (t) = 3 years Rate of Interest (R) = 5% We know that Putting all above values in this equation A = 40000 ( 1 + 5/100 ) 3 A = 40000 ( 105 / 100 ) 3 A = 40000 ( 21 / 20 ) 3 A = 40000   x 21/20 x 21/20 x 21/20 A = 5 x 21 x 21 x 21 A = Rs. 46,305 Now, CI = Amount - Principle CI =Rs. (46305 – 40000) CI = Rs. 6305

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